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4x^2-5.8x+1.44=0
a = 4; b = -5.8; c = +1.44;
Δ = b2-4ac
Δ = -5.82-4·4·1.44
Δ = 10.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5.8)-\sqrt{10.6}}{2*4}=\frac{5.8-\sqrt{10.6}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5.8)+\sqrt{10.6}}{2*4}=\frac{5.8+\sqrt{10.6}}{8} $
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